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Find the product of the reaction of dimethyl ketone i.e. $\ce{CH3C(O)CH3}$ with $\ce{NaNH2}.$

Should I do nucleophilic addition and form the product in the picture?

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  • $\begingroup$ I'm not sure what you are thinking would be substituted. There are no good leaving groups on dimethyl ketone. Given that sodium amide is a strong base, you should ask yourself how dimethyl ketone can act as an acid, and what reactions could occur from there. I'll give you a hint: there should be a nucleophilic addition step. $\endgroup$ – ringo Apr 23 '19 at 3:50
  • $\begingroup$ Sodamide is a strong base and so I believe it will deprotonate any organic compound and form a sodium salt of that organic compound. $\endgroup$ – Nilay Ghosh Apr 23 '19 at 4:13
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    $\begingroup$ try thinking on 1) $\ce{2*CH3COCH3}$ in presence of soda amide and 2) ofcourse what @ringo said is also true. $\endgroup$ – glucose Apr 23 '19 at 6:11
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    $\begingroup$ chegg.com/homework-help/questions-and-answers/… $\endgroup$ – Nilay Ghosh Apr 23 '19 at 9:48
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    $\begingroup$ It's just aldol condensation. $\endgroup$ – user600016 May 7 '19 at 6:40

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