Find the product of the reaction of dimethyl ketone i.e. $\ce{CH3C(O)CH3}$ with $\ce{NaNH2}.$
Should I do nucleophilic addition and form the product in the picture?
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$\begingroup$ I'm not sure what you are thinking would be substituted. There are no good leaving groups on dimethyl ketone. Given that sodium amide is a strong base, you should ask yourself how dimethyl ketone can act as an acid, and what reactions could occur from there. I'll give you a hint: there should be a nucleophilic addition step. $\endgroup$– ringoApr 23, 2019 at 3:50
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$\begingroup$ Sodamide is a strong base and so I believe it will deprotonate any organic compound and form a sodium salt of that organic compound. $\endgroup$– Nilay GhoshApr 23, 2019 at 4:13
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1$\begingroup$ try thinking on 1) $\ce{2*CH3COCH3}$ in presence of soda amide and 2) ofcourse what @ringo said is also true. $\endgroup$– glucoseApr 23, 2019 at 6:11
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1$\begingroup$ chegg.com/homework-help/questions-and-answers/… $\endgroup$– Nilay GhoshApr 23, 2019 at 9:48
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2$\begingroup$ It's just aldol condensation. $\endgroup$– user600016May 7, 2019 at 6:40
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