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This is about a titration. The base titrant used is sodium hydroxide.

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closed as off-topic by Jon Custer, user55119, Todd Minehardt, A.K., Mithoron Apr 14 at 21:53

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You do not assume 100% ionization of acetic acid during titration. Acetic acid is a weak acid. Look at this equilibrium

$\ce{CH3COOH <=> H+ + CH3COO-}$

The base, $\ce{NaOH}$, keeps consuming $\ce{H+}$ during a titration, as a result acetic acids keeps on providing $\ce{H+}$ to maintain the equilibrium in water until all the acetic acid is converted into acetate ion.

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