Partial oxidation of toluene

While reading the preparation of phenol from cumene by reaction with $$\ce{H2O2}$$ or partial oxidation, I was curious to find out why toluene wasn't used.

I checked the literature and found that benzaldehyde would be formed in the case of toluene [1, 2].

Why does benzaldehyde form in the case of toluene? Does the peroxide formed after initial oxidation become benzaldehyde due to its instability? Why doesn't acetophenone form from the peroxide formed in cumene?

References

1. Sun, H.; Blatter, F.; Frei, H. Selective Oxidation of Toluene to Benzaldehyde by $$\ce{O2}$$ with Visible Light in Barium(2+)- and Calcium(2+)-Exchanged Zeolite Y. Journal of the American Chemical Society 1994, 116 (17), 7951–7952. https://doi.org/10.1021/ja00096a084.
2. Wang, X.; Wu, J.; Zhao, M.; Lv, Y.; Li, G.; Hu, C. Partial Oxidation of Toluene in $$\ce{CH3COOH}$$ by $$\ce{H2O2}$$ in the Presence of $$\ce{VO(Acac)2}$$ Catalyst. The Journal of Physical Chemistry C 2009, 113 (32), 14270–14278. https://doi.org/10.1021/jp9028062.

Firstly, if we delve into the mechanism of the oxidation of Cumene, we'll find that there is a rearrangement step in the mechanism. The rearrangement occurs when one of the oxygen in hydroperoxide gets protonated and leaves as water. If you now think carefully, there are both the possibilities of migration of Phenyl and methyl group to the oxygen. But Phenyl has certainly more migratory aptitude than methyl, and also the carbocation formed after the rearrangement is stable, as it has two methyl group on the $$\alpha$$-position to stabilise by electron release and one oxygen atom to stabilise it via donation of lone pair. Thus the migratory aptitude and stability of the carbocation formed both drive the rearrangement to prefer the phenyl migration. Therfore acetophenone is not formed due to unfavoured methyl migration.