Is it possible to make potassium ethoxide by mixing $\ce{KOH}$ and $\ce{EtOH}$ in the presence of a dehydrating agent like $\ce{MgSO4}$ or $\ce{CaO}$ or $\ce{K2CO3}$?

The easy way is adding metallic potassium to ethanol. But nobody likes to deal with potassium or hydrogen.

My understanding is that added $\ce{KOH}$ reacts with $\ce{EtOH}$ in a reversible way. But if there is a water absorber the product water is gone so the reaction moves to the right side.

$$\ce{C2H5OH + KOH <=> C2H5OK + H2O}$$

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    $\begingroup$ Better way is buy it: Sigma-Aldrich sells it in 95% pure form for USD 39.90/100 g. $\endgroup$ – Mathew Mahindaratne Apr 7 at 18:04
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    $\begingroup$ What about ethanol being absorbed? $\endgroup$ – user55119 Apr 7 at 18:43

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