30mL 3M acetic acid (pka 4.7) is added to 50mL 2M NaOH. what is the resulting pH
b) between 2 and 7
can someone explain how to actually solve for pH? the solution describes doing this as a limiting reagent problem in which you solve for the moles of acetic acid and sodium hydroxide.
I'm just a little lost because doesn't acetic acid form its own equilibrium? So doesn't acetic acid form an equilibrium, which means that the actual acid in solution is not that which you calculate from simply multiplying the initial concentration by the initial volume?