In the last step in Victor Mayer test for 2° alcohol, why do we need to add an alkali like NaOH? Isn't pseudo nitrolic acid that is formed already blue in colour?

What would be the reaction of alkali with pseudo nitrolic acid?

I thought that no reaction would occur as pseudo nitrolic acid has no acidic hydrogen, but almost all sources say that it reacts with alkali giving blue colouratiom, without specifying the product formed.

  • 4
    $\begingroup$ Maybe it is to distinguish between nitrolic acid and pseudonitrol. Nitrolic acid reacts with NaOH to form sodium salt of nitrolic acid which is red in color. Pseudonitrol does not react with NaOH and thus retains blue color. $\endgroup$ Mar 31 '19 at 17:21
  • $\begingroup$ Got it. Thanks. $\endgroup$
    – user600016
    Apr 1 '19 at 1:06

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