Should the fact that all atoms involved having an octet, or the rule that more electronegative element should have negative charge and less electronegative element have positive charge, be given greater priority while determining the stability of resonance structures?  Then what shall be the stability order of the following questions a and b?

  • $\begingroup$ No formal charges if possible. The point is that when all atoms have octet and no charge separation, then that structure is a very good description for the real molecule. It will have an important weight and even more so if it happens for it to have degenerate companion, as in aromatic rings. Beside this concept, common (qualitative) rules are easily found. $\endgroup$ – Alchimista Mar 31 '19 at 9:08
  • $\begingroup$ Start by looking for structure with most complete octets then most number of bonds then look for if they have unlikely positive or and unlikely negative charge on the more electronegative and more electropositive atom respectively and then look for charge seperation $\endgroup$ – Aditya Garg Mar 31 '19 at 13:32
  • $\begingroup$ So what would be the answer of the above two questions? $\endgroup$ – Anonymous Mar 31 '19 at 17:27
  • $\begingroup$ I think I have answered. $\endgroup$ – Alchimista Mar 31 '19 at 18:31

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.