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Does Ammonium Acetate, a salt of a weak base and weak acid, undergo both hydration and hydrolysis in aqeous solution? What is meant by the statement that " Some hydration reactions are hydrolysis"

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    $\begingroup$ Hydrolysis and hydration are quite totally unrelated. $\endgroup$ – Ivan Neretin Mar 31 at 8:34
  • $\begingroup$ :-) Quite or totally ? :-) Both involve water. $\endgroup$ – Poutnik Mar 31 at 11:27
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  • Hydrolysis is reaction with water, forming usually 2 different reaction products. It can be also named decomposition by water.

  • Hydration is (usually) reversible chemical bonding of water. It can be also named water addition.

  • One action of above can preceed or follow the other. If the hydration step preceeds hydrolysis in the reaction kinetics, the distinction may look vaque from some points of view.

  • Ammonium acetate undergo hydrolysis.

$$ \begin{align} \ce{CH3COONH4 &-> CH3COO- + NH4+} \\ \ce{CH3COO- + H3O+ &<=> CH3COOH + H2O } \\ \ce{CH3COO- + H2O &<=> CH3COOH + OH- } \\ \ce{NH4+ + H2O &<=> NH3 + H3O+} \\ \ce{NH4+ + OH- &<=> NH3 + H2O} \\ \ce{2 H2O &<=> H3O+ + OH-} \end{align} $$

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  • $\begingroup$ Please note that $\ce{<->}$ arrow denotes resonance. For equilibrium or reversible reactions in general $\ce{<=>}$ is more suited (also it won't hurt to align a set of related reactions about the arrow marks:) ). $\endgroup$ – andselisk Mar 31 at 11:00
  • $\begingroup$ Yes, I know, I have forgotten to use =. Also, it does not hurt if it is not aligned on the phone. :-) The markdown script is not available. $\endgroup$ – Poutnik Mar 31 at 11:05
  • $\begingroup$ Well, you just confirmed the fact that phones are poorly suited for content creation:) $\endgroup$ – andselisk Mar 31 at 11:08
  • $\begingroup$ I have never needed that confirmation :-) But I am not going to publish my answer either. Additionally, the web editor alone is poorly suited either. :-) $\endgroup$ – Poutnik Mar 31 at 11:10
  • $\begingroup$ I have never remembered until now, what is right, \align{begin}, or \begin{align} $\endgroup$ – Poutnik Mar 31 at 11:34

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