# molecular orbital theory [closed]

i read in my textbook that the energy diagram of moleculal orbits is different for atoms nitrogen and below them. my question is which one of the energy diagrams to use in heteronuclear compounds like CO?

## closed as unclear what you're asking by Mithoron, andselisk♦, Karsten Theis, A.K., Soumik DasMar 24 at 3:52

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• I'm assuming you only looked at homonuclear molecules ($\ce{O2}$, $\ce{H2}$) so far. The atomic orbitals are of rather different energies in $\ce{C}$ and $\ce{O}$ just because the nuclear charge is different (consider the ionization energies). That is why I don't expect anyone to produce a decent orbital diagram without performing some quantitative computational chemistry first. – TAR86 Mar 22 at 6:43

It depends on how many electrons your compound has. In $$\ce{O2}$$ , there are 16 electrons. Likewise all compounds with more than 16 electrons follow the $$"\ce{O2}"$$ diagram and those with less than 16 follow the other diagram.