Suppose I had a solid whose molecules did not have rotational freedom. But if I were able to make it so that the molecules had rotational freedom ceteris paribus, is there a way to tell how the melting point would change compared to the original solid. Here I assume that the molecules have rotational freedom in the liquid phase always.

  • $\begingroup$ It should increase as for entropy of the melting should diminish. Assuming nothing else change in the forces leading to the solid, which seems magic. $\endgroup$ – Alchimista Mar 11 '19 at 8:43

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