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I built a galvanic cell using 0.01 M solutions of copper sulfate and zinc sulfate. I used copper and zinc electrodes and immersed them into the proper solutions (copper into copper sulfate, zinc into zinc sulfate).

I used approximately 30 mL of each solution and put them into separate beakers. I connected the solutions using a salt bridge that was filled with 0.01 M potassium nitrate solution. I used cotton to cover the ends of the salt bridge (a plastic tube).

I measured the voltage across the copper and zinc electrodes and I got around 1 V. However, there is no current being produced according to an ammeter. The galvanic cell cannot light up a small light bulb for instance.

Furthermore, I took voltage measurements over a 50 minute period and the the voltage looked relatively constant throughout the period, though very slightly lower at the end.

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  • $\begingroup$ Just increase the concentrations! Use at least 0.1 molar! $\endgroup$ – Ed V May 30 at 18:56
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Your small copper-zinc cell may not light up a bulb as often shown in textbooks. Check your ammeter settings, it must show some current. How are you connecting it in series? voltmeter is connected in parallel. Now an interesting question. Imagine you join 12 (e.g., Duracells) in series to generate about 12 Volts. Can one start a car with 12 Duracells? Why do you need a large car lead-acid battery? The answer lies in current. Same potential difference does not mean same amount of current supply. You may think 1 V is close to an ordinary cell, your single copper-zinc cell cannot supply enough current to even light up a bulb. Cell potential is a thermomdynamic concept. Current supply is a kinetic issue-how fast the electrons transfer to or from electrodes. Now you can think of the reason why there is no commercial battery made from zinc and copper. See Daniell cell for an interesting history. Check the size of electrodes in Daniell cells.

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    $\begingroup$ Is there a way I could improve the current? Will increasing the size of the electrodes increase current? $\endgroup$ – Labrockstar Mar 9 at 14:09
  • $\begingroup$ Yes, increasing the size will increase current, or you can make two or three cell and connect in series. $\endgroup$ – M. Farooq Mar 9 at 14:42
  • $\begingroup$ How will connecting the cells in series increase the current? How is the kinetics of the electrons affected by adding cells? $\endgroup$ – Labrockstar Mar 10 at 5:45
  • $\begingroup$ The kinetics remains the same, however if you have 2 Duracells, each of 1.5 V, your connect them in series, the voltage is now 3.0 V. If the resistance of your load is constant (like a bulb), by Ohm's law, current also increases, V= IR. $\endgroup$ – M. Farooq Mar 10 at 5:59
  • $\begingroup$ Thanks for the information. Can you describe the kinetics of the electrons in the cell? $\endgroup$ – Labrockstar Mar 10 at 6:09
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you can't get the filament bulb glue even a LED doesn't

why :

there is 2 things:

1/ low voltage

the LED need minimum voltage of 1.2 v to 1.6 v to light up

2/ big internal resistor (low current)

the filament lamp need more current to light up; and in your case there isn't because of the internal resistor of the cell; ie your salt bridge contain cotton to cover the ends of the salt bridge which is a big internal resistance (few ohms) in that way you can't get high current only a voltage between the electrodes

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  • $\begingroup$ Good catch, the cotton balls must be huge resistance. $\endgroup$ – M. Farooq Mar 10 at 14:14

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