I am trying to find the $K_\mathrm{b}$ for 50 g of glucose dissolved in 1 kg of ethanol, given the change in boiling point is $\pu{2.2 °C}$. The molality is therefore 0.278. But what is the ionic factor $(i)$? I was told it is the number of ions, so I tried 24, but the answer did not match up with the accepted value.

  • $\begingroup$ Glucose doesn't ionize when dissolved, so it would be 1. @VikramKaushik $\endgroup$
    – Tyberius
    Mar 13, 2019 at 17:35

1 Answer 1


A more appropriate name for the ionic factor is the van't Hoff factor of colligative properties. In the simplest terms, it is the number of particles created after being dissolved in the solution. Since glucose is not an ionic compound, it does not dissociate, therefore $i=1$ (meaning one glucose molecule stays one glucose molecule).


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