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I thought the formula for this $\ce{C11H15}$, but it's not. I need assistance in finding the proper formula:

2-ethynyloctahydro-1H-indene

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  • $\begingroup$ You forgot the $\ce{H}$ on the triple bond! :-) $\endgroup$ – Mathew Mahindaratne Feb 16 '19 at 6:16
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I suspect you forgot one hydrogen at the terminal carbon in alkyne group $\ce{R-C#C-H}$. With this in mind the formula would be $\ce{C11H16}$:

Structure with implicit hydrogens

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