# How do I get a 20% ratio of sodium bisulfate with 1 gallon water? [closed]

How many lbs do I add to 1 gallon of water to get a 20% sodium bisulfate ratio? I am in the middle of anodizing some aluminum.... I just threw the whole 3 lbs in... hopefully it works... I ended up doing a 2 gallon to 3 lb ratio... is this good? It is very cloudy looking

Picture for proof this is not a homework question like the person in the comments below wrongly assumed vs just helping with the question:

## closed as off-topic by andselisk♦, Soumik Das, Tyberius, Mithoron, user55119Feb 14 at 16:37

This question appears to be off-topic. The users who voted to close gave this specific reason:

If this question can be reworded to fit the rules in the help center, please edit the question.

• This is a homework question. We have a policy which states that ‎you should show your thoughts and/or efforts into solving the problem. It'll make us certain that ‎we aren't doing your homework for you. Otherwise, this question may get closed.‎ Please edit in your full reasoning or thoughts on this. – andselisk Feb 14 at 4:15
• actually no its not... i am in the middle of anodizing some aluminum and want to know now... I just ended up throwing the whole 3 pounds in... hopefully it works – Jeff Feb 14 at 4:22
• What percentage you need to make? Is it $w/w$ or $w/v$? – Mathew Mahindaratne Feb 14 at 4:28
• I do not know... they say just a 20% solution of sodium bi-sulfate to anodize (this method is suppose to be safer than using acid) observationsblog.com/sciencetechnologyexperiments/… I suck at this math type stuff... I am literally sitting over here with a bucket full of this stuff waiting to make sure I got it right... bout to say F' it and try it anyway and see what happens. – Jeff Feb 14 at 4:30
• @Jeff the idea of a homework question on the site is essentially a question where you state a problem without context and/or the efforts you have made to solve the problem. – Tyberius Feb 14 at 14:50

$$\dfrac{4000}{160} = 25$$
$$25 \times 40 \text{ grams}= 1000 \text{ grams} \approx 2.2 \text{ lbs/(gallon of water)}$$