# Ozonolysis products of ortho-methyl toluene

What yield of different products will I obtain upon ozonolysis of o-methyl toluene?

Assuming 2 moles of the compound to react(each with different positions of double bonds), I get the possible products from 2 moles of o-methyl toluene:

1. Methyl glyoxal- 2 moles
2. Dimethyl glyoxal- 1 mole
3. Glyoxal- 3 moles

Different contributing stuctures of the benzene ring are generating different sets of products(obviously). The methyl groups are either together or on separate molecules altogether.

I wonder if all possible products will be generated equally(same as molar ratio), or for some reason the yield of certain products will be favoured over others.

• @Waylander Yes, reductive workup. So $Me_2S$ or $Zn/H_2O$ – William R. Ebenezer Feb 8 at 16:13