# How do I explain these bond angles in SF4 and SOF4?

From here and here I found that the bond angle between the equatorial $$\ce{F}$$'s in $$\ce{SF4}$$ is less than that in $$\ce{SOF4}$$. I understand that is because of greater repulsion by lone pair than by double bond.

But the angle between the axial $$\ce{F}$$'s in $$\ce{SF4}$$ is more than that in $$\ce{SOF4}$$. I am not able to understand why is this so. Shouldn't the lone pair repel more than double bond here too?

• I'd say the effects are too subtle to be explained that easily. – Ivan Neretin Feb 6 at 5:37
• You are trying to compare 2 different geometries: one with 4 vertices and the other with 5! Of course angles won't match – SteffX Feb 6 at 14:44
• @SteffX Try counting again and don't forget about lone pair. – andselisk Feb 6 at 15:05
• I suspect that some subtle molecular orbital effects are going on here. Oxygen has two pairs of pi-symmetry electrons to donate and is tending to pull the fluorines towards a symmetric structure to optimize that interaction. – Oscar Lanzi Feb 6 at 15:25