# Why is lead(II) present in two groups of cation analysis? [closed]

Well, I found that lead cation $$\ce{Pb^2+}$$ is present in both group 1 and group 2 of cation analysis. But why?

## closed as unclear what you're asking by Jon Custer, aventurin, Mithoron, Tyberius, airhuffJan 29 at 20:11

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Simply because lead(II) fits both analytical groups:

One reason for putting lead in both groups is that the chloride is somewhat of a borderline case in terms of being insoluble enough to appear in Group I. Group II represents a more complicated analysis but is more sensitive for lead.

• Lead (II) chloride has enough solubility so it could slip through the cracks in Group I. Group II where the sulfide is precipitated is more sensitive. – Oscar Lanzi Jan 29 at 15:46
• @OscarLanzi You are right, probably it would be worth adding that there are no sharp margins between these 6 groups and various sources add or remove cations from one group to another arbitrarily. – andselisk Jan 29 at 15:49