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How does an uncharged non-polar molecule that has a quadrupole moment (such as carbon dioxide) behave in an electric field? I know that in a homogeneous electric field, ions travel while dipoles orient along the field (rotate) and non-polar molecules are not affected.

What kind of electrical field, if any, would exert a force on a molecule with a quadrupole moment?

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    $\begingroup$ One application to selectively bind to carbon dioxide rather than dinitrogen (which does not have a strong quadrupole) is linked to in this report. $\endgroup$ – Karsten Theis Jan 26 at 15:23
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Different moments of a charge distribution couple to different components of the external electric field. In the case of the quadrupole moment, the coupling is to the gradient of the electric field (EFG). Such an interaction is for instance relevant in NMR of quadrupolar nuclei, NQR (not to be confused with naked quad run, according to the wikipedia - o tempora, o mores) and Mössbauer spectroscopy, although those techniques consider the nuclear quadrupole moment.

In the case of atoms and molecules without permanent electric monopoles or dipoles, EFG interactions with permanent quadrupoles are the leading field-multipole interaction energy term (ignoring dispersion terms, ie induced dipole-induced dipole). In some cases such interactions can be of particular importance, for instance in aromatic compounds (see Kocman et al. cited below).

The quadrupole moment has been measured in $\ce{CO_2}$, see eg Chetty cited below, which includes experimental methods.

References

Electric quadrupole moment of graphene and its effect on intermolecular interactions M. Kocman, M. Pykal and P. Jurecka Physical Chemistry Chemical Physics Vol. 16, 2014

N. Chetty and V.W. Couling Measurement of the electric quadrupole moments of CO2 and OCS Molecular Physics Vol. 109 (5), 2011, 655–666

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    $\begingroup$ Not a bad answer except that it doesn't tell us what happens when there is coupling. $\endgroup$ – matt_black Jan 26 at 14:41
  • $\begingroup$ @matt_black I don't fully understand your question. The energy of the molecule is altered by the interaction of an EFG with the quadrupole moment, naturally. There is an associated force if the orientation of the EFG and quad tensors is not that of the minimum energy state. $\endgroup$ – Buck Thorn Jan 26 at 14:50
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    $\begingroup$ IF a molecule with a dipole interacts with the strong electric field in, for example, a microwave oven, it ends up absorbing a lot of the radiation causing a lot of warming. What sort of effects do we see for radiation interacting with quadroploes? how big are they and what are the things we observe? $\endgroup$ – matt_black Jan 26 at 14:55
  • $\begingroup$ @matt_black Ok, I see your point. The question is what strength of EFG would lead to a non-negligible energy compared to kT. That will take some additional thought. The quad constant is provided in the reference I cite, so it's a question of finding the expression for the interaction with the EFG and solving. $\endgroup$ – Buck Thorn Jan 26 at 15:16
  • $\begingroup$ The paper showed by Chetty and Couling showed a temperature-dependent effect. I'm suppose the field orients the molecule, and at low temperature it is more oriented than at higher temperatures. But that's just a guess from skimming the paper. $\endgroup$ – Karsten Theis Jan 26 at 15:21
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To determine the force on an arbitrary multipole moment, we first expand the E-field in a Taylor-series around the point $\vec{r}=0$:

$$\vec{E}(\vec{r})=\vec{E}_0+\vec{r}\cdot(\nabla\vec{E})_0+\frac{1}{2}\vec{r}\vec{r}:(\nabla\nabla\vec{E})_0+...$$

where the number of dots in the product denotes how many indices to contract over. We can then determine the force using this expansion, since it is just the charge multiplied by the E-field:

$$\vec{F}=q\vec{E}_0+\vec{\mu}\cdot(\nabla\vec{E})_0+\frac{1}{2}\mathbf{\Theta}:(\nabla\nabla\vec{E})_0+...$$ Typically, people use the traceless quadrupole, which would add an additional factor of $\frac{1}{3}$ in the third term, but I'm going to work with the basic definition throughout. So this shows that a quadrupole subject to a large electric field double gradient (not sure of the correct terminology for this) will experience a force even if it is charge neutral and has no net dipole.

For completeness, we can also write the energy since the force is just the gradient of the energy:

$$W=q\phi-\mu\cdot\vec{E}-\frac{1}{2}\mathbf{\Theta}:(\nabla\vec{E})+...$$ where we see, as TryHard said, that the E-field gradient interacts with the quadrupole.

As an aside, one can also obtain the torque (cross product of force and r) on an arbitrary multipole: $$\vec{T}=\vec{\mu}\times\vec{E}_0+\frac{1}{2}\mathbf{\Theta}\dot{\times}(\nabla\vec{E})_0+...$$

(I'm using the nonstandard notation $A\dot{\times}B$ to mean $\sum_{ijkl}\epsilon_{jkl}e_iA_{jl}B_{lk}$, where $\epsilon_{jkl}$ is the Levi-Civita operator and the $e_i$ are a set of orthonormal unit vectors). This suggests that a quadrupole will experience a torque when interacting with a field gradient.

For more information on this, I would read chapter 3 of Jeanne McHale's Molecular Spectroscopy. There are some typos and notational quirks(e.g. in the equation for torque, McHale just writes a cross product for the 2nd term, which isn't defined between matrices), but its overall a good book to give background in classical electrostatics and a quantum mechanical description of spectroscopy.

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