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Why $CH_3OH$ is more acidic than $H_2O$ while the same is opposite for other alcohols?

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The question is based on the assumption, that water has a pKa of 15.7 which is usally not correct.

As a paper mentioned in this thread What is the Real Pka of WATER the pKa of water in water should be 14.It might be different when water is a reactend in organic solvents, for that the paper mentioned by the thread author is helpful.

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Like other alcohols Methanol is also a weaker acid than water; sodium methoxide undergo easy hydrolysis with water forming methanol and sodium hydroxide, the equilibrium being more in favour of the products. Since methoxide ion is a stronger base than hydroxide the parent acid methanol must be weaker acid than water $\ce{CH3O^-Na^+ + HOH<=>CH3OH + Na^+OH^-}$

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