# Methanol vs water. Acidic strength [duplicate]

Why $$CH_3OH$$ is more acidic than $$H_2O$$ while the same is opposite for other alcohols?

Like other alcohols Methanol is also a weaker acid than water; sodium methoxide undergo easy hydrolysis with water forming methanol and sodium hydroxide, the equilibrium being more in favour of the products. Since methoxide ion is a stronger base than hydroxide the parent acid methanol must be weaker acid than water $$\ce{CH3O^-Na^+ + HOH<=>CH3OH + Na^+OH^-}$$