3
$\begingroup$

Down the halogen group , electropositive character increases , then why is it that Fluoride ion is the least stable ? The counter arguement is that fluoride ion has four lone pairs and a small size which makes it least stable.Down the group , since atomic size increases the extra electron is stabilized. In all such stability trends there are multiple counteracting factors , how to decide which one to give more weightage ?

$\endgroup$

1 Answer 1

4
$\begingroup$

Actually, the answer is a bit more nuanced. If we observe the pKb values (i.e. tendency to form HX from X-, where X is a B-L base) it is pretty clear that F- would form HF very quickly.

The explanation is that I- would have a much larger area to balance out the negative charge compared to F-, and the anion would be more stable as a result.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.