# Inexact differential-path function

From Wikipedia:

an inexact differential cannot be expressed in terms of its antiderivative for the purpose of integral calculations

What's the mathematical reason that inexact differential cannot be expressed in terms of its antiderivative? Not enough information? Too complicated? $$\mathrm{d}U$$ is an exact differential. If you integrate $$\mathrm{d}U$$, what will you get then?

• This question would be better off in a part of stack exchange devoted to maths – Nuclear Chemist Jan 5 '19 at 13:13

As for integrating over $$dU$$, $$U$$ is a state function and so you can apply the fundamental theorem and solve the integral using the antiderivatives at the end points.