# 1-Methyl-4-nitrobenzene proton NMR spectrum confusion

I wanted to analyse and suggest the peaks for the NMR spectrum and ran into a problem.

I knew that the methyl $$\ce{CH3}$$ produces a singlet peak with integration $$3$$ but when I ran into the benzene protons, I thought that the two equivalent protons (one on each side) would split into a doublet (considering if coupling occurs through 3 bonds or fewer only).

So this was my solution to the problem:

• s, $$\ce{3H}$$, integrated $$3$$, ppm $$2.0$$ due to $$\ce{CH3}$$ group.
• d, $$\ce{3H}$$, integrated $$2$$, ppm $$7.2$$ due to $$\ce{H}$$ on benzene furthest from $$\ce{NO2}$$.
• d, $$\ce{3H}$$, integrated $$2$$, ppm $$7.9$$ due to $$\ce{H}$$ on benzene closest to $$\ce{NO2}$$.

However, the spectrum answer given by the mark scheme was as such:

Where have I made a mistake?