Amidines can be thought of as carboxylic acid derivatives with the carbonyl oxygen replaced by a nitrogen and hydrogen atom; amidines exhibit conjugation.
Amidines are more basic (less acidic) than amines and amides by a factor of around ${10^{3}}$ and ${10^{12}}$, respectively (from pKas).
I would naturally think that conjugation would lower the energy level of MO containing the lone pair; thus, the lone pair would be more bound to the nucleus and less available to deprotonate.
This is an argument similar to explaining why pyridine is less basic than piperidine; $\ce{N}$ is $sp^{3}$ hybridized in piperidine but $sp^{2}$ hybridized in pyridine. Since $sp^{2}$ orbitals have less p character than $sp^{3}$ orbitals (2/3 vs 3/4), the lone pair on $\ce{N}$ in pyridine is at a lower energy level than the lone pair on $\ce{N}$ in piperidien, and pyridine is less basic than pyridine.
Although I realize that the positive charge on the amidine is stabilized by conjugation (as explored by a previous post comparing the basicity of amidines and amides), wouldn't my reasoning with MO theory outlined above suggest a lowering of the basicity of amidines?
References
Clayden, J., Greeves, N., Warren, S. Organic chemistry, 2nd ed.; Oxford University Press: New York, 2012.