When the vapours of a 1°,2°,3° alcohol are passed over red hot Cu powder at 573K, 1°,2° alcohol undergo dehydrogenation to form an aldehyde or ketone respectively and 3° alcohol undergoes dehydrationto form an alkene. Why does this happen?

I tried to read a bit about the mechanism and found out that in the case of 1°,2° the OH group is not lost and then by tautomerism aldehyde and ketone is formed. Why isn't the OH group lost? Why is this not the case for 3° alcohol?


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.