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A compound $\ce X$ of formula $\ce{C2H5NO2}$ on treatment with $\ce {HNO2}(\ce{NaNO2}+\ce{HCl})$ gives off an inactive gas $\ce Y$ and forms $\ce Z$. When heated with soda lime, $\ce X$ gives $\ce{A(CH5N)}$ soluble in acid. Find the true statements :

  1. $\ce A$ answers carbylamine test.
  2. $\ce X$ is an amino acid.
  3. $\ce Y$ is $\ce{CO2}$.
  4. $\ce Z$ is a hydroxyl acid.

My attempt :

$\ce X$ is Glycine.

$\ce A$ is methyl amine.

$\ce Y$ is dintrogen.

$\ce Z$ is 2-hydroxy ethanoic acid.

Hence, Correct options are : $1,2,4$ But the answer given is $2,4$.

Can anyone help me?

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You are indeed correct. $\mathbf{HOOC-CH_2-NH_2} \;\mathbf{(X)}\xrightarrow{HNO_2} \mathbf{HOOC-CH_2-OH}\;\mathbf{(Z)} + \mathbf{N_2} \;\mathbf{(Y)}$

$\mathbf{HOOC-CH_2-NH_2} \;\mathbf{(X)}\xrightarrow{soda\;lime}\mathbf{CH_2-NH_2}\;\mathbf{(A)}$

$Also, \mathbf{A}+ \mathbf{CHCl_3} +\mathbf{3KOH}\xrightarrow{Heat} \mathbf{CH_3-NC} +\mathbf{3KCl}+ \mathbf{3H_2O}$. Methylamine does give the carbylamine test.

http://en.wikipedia.org/wiki/Carbylamine_reaction

Clearly, the answer given must be wrong.

The correct options are 1,2 and 4.

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