4
$\begingroup$

A compound $\ce X$ of formula $\ce{C2H5NO2}$ on treatment with $\ce {HNO2}$ $(\ce{NaNO2}+\ce{HCl})$ gives off an inactive gas $\ce Y$ and forms $\ce Z$. When heated with soda lime, $\ce X$ gives $\ce{A(CH5N)}$ soluble in acid. Find the true statements :

  1. $\ce A$ answers carbylamine test.
  2. $\ce X$ is an amino acid.
  3. $\ce Y$ is $\ce{CO2}$.
  4. $\ce Z$ is a hydroxyl acid.

My attempt :

$\ce X$ is glycine.

$\ce A$ is methyl amine.

$\ce Y$ is dinitrogen.

$\ce Z$ is 2-hydroxy ethanoic acid.

Hence, correct options should be : $1,2,4$. But the answer given is $2,4$.

Can anyone help me to understand if and where I went wrong?

$\endgroup$
3
$\begingroup$

You are indeed correct.

$\ce{HOOC-CH2-NH2(X) ->[HNO2] HOOC-CH2-OH (Z) + N2(Y)}$

$\ce{HOOC-CH2-NH2(X) ->[soda lime] CH2-NH2(A)}$

Also, $ \ce{(A) + CHCl3 + 3KOH ->[Heat] CH3-NC + 3KCl + 3H2O}$.

Methylamine does give the carbylamine test.

So clearly, the answer given must be wrong.

The correct options are 1,2 and 4.

|improve this answer|||||
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.