A compound $\ce X$ of formula $\ce{C2H5NO2}$ on treatment with $\ce {HNO2}$ $(\ce{NaNO2}+\ce{HCl})$ gives off an inactive gas $\ce Y$ and forms $\ce Z$. When heated with soda lime, $\ce X$ gives $\ce{A(CH5N)}$ soluble in acid. Find the true statements :

  1. $\ce A$ answers carbylamine test.
  2. $\ce X$ is an amino acid.
  3. $\ce Y$ is $\ce{CO2}$.
  4. $\ce Z$ is a hydroxyl acid.

My attempt :

$\ce X$ is glycine.

$\ce A$ is methyl amine.

$\ce Y$ is dinitrogen.

$\ce Z$ is 2-hydroxy ethanoic acid.

Hence, correct options should be : $1,2,4$. But the answer given is $2,4$.

Can anyone help me to understand if and where I went wrong?


You are indeed correct.

$\ce{HOOC-CH2-NH2(X) ->[HNO2] HOOC-CH2-OH (Z) + N2(Y)}$

$\ce{HOOC-CH2-NH2(X) ->[soda lime] CH2-NH2(A)}$

Also, $ \ce{(A) + CHCl3 + 3KOH ->[Heat] CH3-NC + 3KCl + 3H2O}$.

Methylamine does give the carbylamine test.

So clearly, the answer given must be wrong.

The correct options are 1,2 and 4.


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