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Is this mechanism will be similar to ozonolysis ?

My try : enter image description here

My Question is will B be the answer ? And what does Me2S do ?

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  • $\begingroup$ Definitely Yes. $\endgroup$ – Soumik Das Nov 28 '18 at 13:05
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    $\begingroup$ Me2S reduces the ozonide and any remaining ozone. I think the reaction will take place on the more electron rich double bond. The product you have drawn is not one of the options offered among the answers. $\endgroup$ – Waylander Nov 28 '18 at 13:20
  • $\begingroup$ @Waylander should the Answer be B ? $\endgroup$ – Chloritone_360 Nov 28 '18 at 13:27
  • $\begingroup$ I highly doubt that the reagent in the first step is O2, and if that's the case, then it's oxidation reaction. But, I'm not sure! $\endgroup$ – rv7 Nov 28 '18 at 13:45
  • $\begingroup$ @rv7 its O3 ,Ozonolysis will happen I think $\endgroup$ – Chloritone_360 Nov 28 '18 at 13:47
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The first part of your question has been answered in the comment, as for the part about what does $\ce{Me2S}$ do:
The mechanism used here is reductive ozonolysis and $\ce{Me2S}$ acts a reducing reducing agent itself getting oxidised to dimethysulphoxide $\ce{(Me)2SO}$ (DMSO).
As for the mechanism of reductive ozonolysis with $\ce{Me2S}$ here's a helpful link.


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