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In the reaction:

$\ce{NH3 + BF3 -> NH3-BF3}$ does the HNH bond angle increase or decrease?

Surely, the FBF bond angle decreases because boron changes from $\ce{sp^2 -> sp^3}$. But how can we comment upon the NHN bond angle? In my first attempt, I expected it to increase because though N still remains in $\ce{sp^3}$ hybridisation lp-bp repulsions are greater than bp-bp repulsions.

But the answer key states that the NHN bond angle will decrease. Please let me know how to determine this.

I couldn't find the bond angle data on net or in JD Lee.

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    $\begingroup$ I think bond angles should increase. $\endgroup$ – Soumik Das Nov 13 '18 at 5:28
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    $\begingroup$ Yes, that's what I think too $\endgroup$ – Archer Nov 13 '18 at 5:50

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