# My confusion regarding Hydrogen peroxide

In Hydrogen peroxide, the oxidation number of oxygen is "-1" instead of "-2".

But it seems to me that, the oxygen atoms have '-2' as their oxidation number as each oxygen atom here is connected to a hydrogen atom and an oxygen atom.

So, what's actually happening here?

If there's any problem in my question please inform me. Thanks!

• @MaxW Sorry, was a typo, edited it – Truth Nov 4 '18 at 16:25
• Here is another way to think about it. Mentally break the O-O bond heterolytically (+/-). Now you have HO- and HO+. HO- has a -2 charge (normal) and HO+ has a zero charge on oxygen since in both cases hydrogen is +1. Oxygen zero, a 2-electron oxidant, will accept 2-electrons from a reducing agent to convert HO+ to HO-. This is why HOOH is an oxidant. E.g., MeSMe + HOOH ---> Me2SO + H2O. – user55119 Nov 4 '18 at 16:45

Each oxygen atom is connected to a hydrogen atom(which develops -1 charge on oxygen and +1 on hydrogen) and to another $$\textbf{oxygen}$$ atom which contributes no charge to both(0 and 0). Similar for other oxygen atom. Hence oxygen state of each oxygen atom is -1 and for each hydrogen atom it is +1.