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In 1 dimension, the curvature of Ψ = K.E. of wave. Is this the case for 2 dimensions and 3 dimensions also? Moreover, is curvature of Ψ = K.E. of wave = 2nd derivative of Ψ?

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  • $\begingroup$ If you drop the usage of the word "curvature" altogether, the rest would be true. $\endgroup$ – Ivan Neretin Oct 20 '18 at 17:33
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    $\begingroup$ I think "curvature" is still used in three dimensions, at least, I've seen it before when discussing KE + PE contributions to the energy... $\endgroup$ – orthocresol Oct 20 '18 at 17:38
  • $\begingroup$ Ivan Neretin slide 19 of this powerpoint, ocw.mit.edu/courses/electrical-engineering-and-computer-science/…, states clearly that curvature of wavefunction = K.E. of wave $\endgroup$ – ETS Oct 20 '18 at 21:03

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