1
$\begingroup$

In this reaction of the alkene, the correct answer is below but I don't understand why it goes to that. This is my thought process - reagents 1 and 2 do oxymercuration demercuration and makes a secondary alcohol, then reagent 3 turns the alcohol into a ketone, and finally reagent 4 and 5 performs nucleophilic addition and turns the alcohol into a tetrahedral with CN attached (my steps I drew below). What am I doing wrong here? Thanks enter image description here

enter image description here

Improve this question
$\endgroup$
2
  • 1
    $\begingroup$ After the Cyanide formation, the last step is basically a hydrolysis step. $\endgroup$
    – Soumik Das
    Oct 14 '18 at 17:41
  • $\begingroup$ thanks for the reply, so does the carboxylic acid replace the CN via hydrolysis ? i am still a bit confused $\endgroup$
    – Jon
    Oct 14 '18 at 18:27
0
$\begingroup$

Check the mechanism of the last reaction here. http://www.chem.ucalgary.ca/courses/350/Carey5th/Ch20/ch20-3-5-1.html

It is not the displacement of nitrile by carboxylic acid(which you do not have, btw). It is the combination of water addition and the displacement of ammonia by second equivalent of water.

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.