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I had a chemistry lab and I did a error. I was supposed to make some $\ce{MnCl2}$ and then used fire to dry it but then some of it turned black, and I am supposed to quantify my error. So I am assuming the reaction to be between $\ce{MnCl2}$ and $\ce{O2}$ but I don't know what they make.

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Heating $\ce{MnCl2}$ in presence of air made it to oxidize and form black manganese oxides.

$$\ce{4MnCl2 + 3O2 ->[\Delta] 2Mn2O3 + 4Cl2}$$

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  • $\begingroup$ You don't get gaseous chlorine this way, only mixture of oxides and chlorides, IMO. $\endgroup$ – Mithoron Oct 5 '18 at 14:45

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