I am not able to solve this question. Here's my working
Have I done this in the right way? Because my textbook gives answer as 4 moles
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Sign up to join this communityI am not able to solve this question. Here's my working
Have I done this in the right way? Because my textbook gives answer as 4 moles
Ok, there are two reactions for the 2 moles of A
$$\ce{A ->[rate\space =\space k_1] 2B}$$
$$\ce{A ->[rate\space =\space k_2] 2C}$$
$$\dfrac{k_1}{k_2} = \dfrac{1}{2}$$
The question asks for the total number of moles of A+B+C when the reaction is 75% complete.
Thus there is 0.5 + 3 = 3.5 moles of A+B+C in the solution when the reaction is 75% complete.
There are 4 moles when the reaction is 100% complete.
So the book answer is wrong.