In Electrophilic Aromatic Substitution reaction (EAS), the choice of catalyst may influence the yield of the desired product.
First of all, note the following data:
Bond dissociation energy (in kJ/mol) -
Al–Br : 429.2
Al–Cl : 502
As the bond dissociation energy for Al–Cl bond is greater, it must be stronger.
Now, consider using aluminium bromide as catalyst for an EAS chlorination.
In the first step, i.e. interaction of chlorine molecule with Lewis acid aluminium bromide, one can't possibly neglect the formation of bromonium ion which may act as electrophile - decreasing yield of chlorobenzene and giving unnecessary side product of bromobenzene. This possibility is supported by thermodynamics, as shown by the data mentioned above.
To make sure that yield of product is maximum and no unnecessary side reactions occur - aluminium chloride catalyst is employed for chlorination and aluminium bromide for bromination.
Hope this answers your question.
P.S.
Correction to @AvnishKabaj's answer:
If I had to give a reason it would be that when the AlCl3-Br2 complex is made there might be a teeny tiny chance that instead of the bromine breaking away the chlorine breaks away.
As per the bond energy data I have, from this exhaustive table ;it is easy to conclude that the bond strength of Al–Cl bond is greater than Al–Br bond. Hence, problems would arise when chlorination is done in presence of aluminium bromide catalyst. In the AlBr3-Cl2 complex, there'd be a teeny tiny chance that instead of the chlorine breaking away, the bromine breaks away. (based on thermodynamic favourability)