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In the hydrogenation of unsaturated compounds with hydrogen gas and a catalyst, the choice of palladium on carbon is able to hydrogenate alkenes and alkynes, but is unable to hydrogenate aromatic compounds. Using rhodium or Raney nickel, however, allows one to hydrogenate aromatics. How does the choice of catalyst affect what kind of unsaturated compounds can be hydrogenated?

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  • $\begingroup$ @Georg I think he wants a mechanistic explanation. $\endgroup$
    – CHM
    Commented Apr 26, 2012 at 21:23
  • $\begingroup$ @Georg: Oh, I assure you I did. Unfortunately I seem to not be reading the right references, since a lot of them just mention "catalyst X works for hydrogenating substrate Y". Now, anything else you can offer, good sir? $\endgroup$
    – user95
    Commented Apr 27, 2012 at 10:30

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The currently accepted hydrogenation mechanism for metal like palladium is the Horiuti-Polanyi mechanism. (image) This mechanism works with good yield for alkenes and alkynes. For an aromatic compound, the activation energy is much higher because the aromaticity of the target molecule is being broken by the first hydrogenation. Indeed, 1,3-cyclohexadiene is very unstable and will revert to benzene and hydrogen instead of continuing to cyclohexane.

Addition of a Lewis Acid makes palladium an acceptable catalyst for the hydrogenation of benzene, however. An intermediate compound with the benzene and the LA is first formed, and hydrogen is added to this intermediate. This paper discusses the mechanism of hydrogenation in the presence of a Lewis Acid.

Rhodium catalysts work slightly differently. They generally have ligands attached that help stabilize the intermediates. You can see a simplified mechanism here and there are papers discussing specific catalysts here and here. Basically, in the case of benzene, the relatively unstable 1,2-cyclohexadiene is held in place on the catalyst until it has been completely hydrogenated.

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  • $\begingroup$ In that Horiuti- Link there is a big error. No D in the upper product, althouh the reaction is +D and -H ! In general, JM asked for heterogenous katalysts, and there is little to no knowlegde besides the phenomenology of results. The problem is the microscopic structure of the Pd or Pt or Ni preparations. $\endgroup$
    – Georg
    Commented Apr 28, 2012 at 7:02

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