14
$\begingroup$

My teacher told me that carbon's tetravalency and high catenation ability makes it special and is the reason why there are millions of compounds of carbon.

1) Silicon is tetravalent too but doesn't create as many compounds as carbon.Why?

2) The textbook says that no other element exhibits the property of catenation to the extent of carbon. Why is this so? Does it just happen magically?

$\endgroup$

1 Answer 1

16
$\begingroup$

There are two key factors that account for the ubiquity of carbon compounds.

  • Bond strengths: Look at the following table of bond strengths and notice how the strength of both carbon-carbon single and double bonds is much greater than the bond strengths found in other molecules.

\begin{array}\hline Typical~Single ~Bond~ Dissociation ~Energies~ (kcal/mole)\\ \hline \end{array} \begin{array}{|c|c|c|}\hline C-C & 83 \\ \hline N-N & 38 \\ \hline O-O & 35 \\ \hline Si-Si & 52 \\ \hline P-P & 50 \\ \hline S-S & 54 \\ \hline \end{array}

\begin{array}\hline Typical~Double ~Bond~ Dissociation ~Energies~ (kcal/mole)\\ \hline \end{array} \begin{array}{|c|c|c|}\hline C=C & 146 \\ \hline N=N & 109 \\ \hline O=O & 119 \\ \hline P=P & 84 \\ \hline \end{array} link to reference

These numbers tell us that carbon-carbon bonds are significantly more stable than other bonds and that the driving force for their formation will be more exothermic. Therefore, large collections of carbon atoms can be bonded together to produce very stable systems.

  • Hybridization: Saying that carbon is tetravalent doesn't fully convey the versatility carbon can display in forming bonds. Hybridization involves a re-mixing of s- and p-orbitals in response to bond formation and this leads to the formation of more stable bonds. Carbon is capable of extensive variation in the hybridization of the bonds it forms, much more so than most other atoms. This wide range in hybridization that is possible for carbon allows it to form much more stable bonds in a wide variety of different structural situations.
    \begin{array}\hline Typical~Carbon-Carbon ~Bond~ Strengths~ (kcal/mole)\\ \hline \end{array} \begin{array}{|c|c|c|}\hline alkane & sp^3 & 84 \\ \hline alkene & sp^2 & 150 \\ \hline alkyne & sp & 200 \\ \hline \end{array}
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.