While reading on order of nucleophilicity of $\ce{RS-}$ and $\ce{RO-}$, I came across this:
Source: Page 355, Organic Chemistry by Jonathan Clayden, Nick Greeves, and Stuart Warren
However, my teacher has said that in polar protic medium, nucleophilicity of $\ce{RS-}$ dominates over $\ce{RO-}$ due to the heavy solvation of oxygen and the relatively low solvation of sulfur. And, in polar aprotic medium, due to the high potential energy of the $\ce{RO-}$ anion, it becomes a better nucleophile than $\ce{RS-}$ anion. (Just like the order of nucleophilicity halide anions).
Although they have given data for reaction in polar protic ($\ce{EtOH}$) medium in the book, I feel like nucleophilicity of $\ce{RS-}$ should still be higher than $\ce{RO-}$, independent of the medium, because of the reason of HOMO-LUMO interaction mentioned in the book (which should be independent of the solvent)
Also, electrostatic interactions must be a less dominating factor than HOMO-LUMO interactions for $S_N 2$ reactions as the C-X bond is not that polar.
In the above data of reaction with $\ce{MeBr}$, the difference in rate is in the order of $10^4$. I feel like that must account for something more than the effect of solvent.
However, I could not find data for the rate of $S_N 2$ in polar aprotic medium. So, in polar aprotic medium, which of $\ce{RO-}$ or $\ce{RS-}$ is more nucleophilic and why?