I wanted to ask some reference about aluminum nitride hydrolysis in water. Specifically I would like to know if there is the formation of radicals or of some other reactive species.
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$\begingroup$ Aluminum nitride $\ce{AlN}$ is made of one ion $\ce{Al^{3+}}$ and one nitride ion $\ce{N^{3-}}$. Both react with $\ce{H2O}$. The reaction is $\ce{AlN + 3 H2O -> Al(OH)3 + NH3}$. What sort of radicals do you want to introduce here ? $\endgroup$– MauriceCommented Sep 21, 2022 at 7:57
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1$\begingroup$ To avoid duplicities, it would help responders if you wrote what you had been already searching for and where you had been already looking for it. $\endgroup$– PoutnikCommented Sep 21, 2022 at 8:24
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$\begingroup$ @Maurice I have learned to take nothing for granted when it comes to chemistry. Many phenomena can be more complex than they appear to be. $\endgroup$– Al1010Commented Sep 24, 2022 at 5:00
1 Answer
I am quoting from this study[1]:
$\ce{AlN}$ powders hydrolyze in moist air at room temperature, resulting in degradation of the powders. The initial hydrolysis product is amorphous $\ce{AlOOH}$, which is further converted to a mixture of polymorphs of $\ce{Al(OH)3}$ (bayerite, nordstrandite, and gibbsite), forming agglomerates around the unreacted $\ce{AlN}$ core. In the hydrolysis each powder shows an induction period, which is attributed to slow hydrolysis of the surface oxide/oxyhydroxide layer. The powders produced by the carbothermal process show the longest induction periods.
$$ \begin{align} \ce{AlN + 2H2O → AlOOH_{amorph} + NH3} & \tag{R1}\\ \ce{AlOOH_{amorph} + H2O → Al(OH)3} & \tag{R2}\\ \\\hline \ce{AlN + 3H2O → Al(OH)3 + NH3}\\ \end{align} $$
You can find a detail explanation of the reaction in that study.
Reference:
- Jinwang Li, Masaru Nakamura, Takashi Shirai, Koji Matsumaru, Chanel Ishizaki and Kozo Ishizaki, Hydrolysis of Aluminum Nitride Powders in Moist Air, 2005, DOI: 10.2240/azojomo0111