I know that there are 2 isomers that $\ce{Ni(PPh3)2Cl2}$ have and they exist in equilibrium. I am tempted to name them cis- and trans- but it does not sound right.
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1$\begingroup$ Given that one isomer is tetrahedral and one is square planar, cis and trans would not be correct as there is no cis/trans in a tetrahedron. See also: en.wikipedia.org/wiki/Dichlorobis(triphenylphosphine)nickel(II) $\endgroup$– Martin - マーチン ♦Jun 19, 2019 at 13:34
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1$\begingroup$ Answer for the question is here chemistry.stackexchange.com/questions/115553/… of the structures is square planar ,while the other is tetrahedral.The square planar complex can both be cis and trans. $\endgroup$– Chakravarthy KalyanJun 19, 2019 at 18:00
1 Answer
A metal phosphine complex, dichlorobis(triphenylphosphine)nickel(II) exists in two isomeric forms (blue and red) based on how you prepared it (Wikipedia). The blue isomer, which is paramagnetic can be prepared by treating hydrated nickel chloride ($\ce{NiCl2.6H2O}$) with triphenylphosphine in alcohols or glacial acetic acid. When allowed to crystallize from chlorinated solvents (e.g., dicloroethane (Ref.1), dicloromethane (Ref.2)), the tetrahedral isomer converts to the square planar red isomer, which is trans and diamagnetic:
References:
- Benedetto Corain, Bruno Longato, Roberto Angeletti, Giovanni Valle, “trans-[Dichlorobis(triphenylphosphine)nickel(II)]•$\ce{(C2H4Cl2)2}$: a clathrate of the allogon of venanzi's tetrahedral complex,” Inorganica Chimica Acta 1985, 104(1), 15–18 (https://doi.org/10.1016/S0020-1693(00)83780-9).
- A. S. Batsanov, J. A. K. Howard, “trans-Dichlorobis(triphenylphosphine)nickel(II) bis(dichloromethane) solvate: redetermination at $\pu{120 K}$,” Acta Cryst. 2001, E57, m308–m309 (https://doi.org/10.1107/S1600536801008741).