How is an an acyl hydrazide converted into an acyl azide in the presence of $\ce{HNO2}$? According to me, the $\ce{-NH2}$ group of hydrazide will get converted into $\ce{-N2+}$ through $\ce{HNO2}$. However, I am unable to proceed after that.
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$\begingroup$ In ChemSE you can Accept a answer by giving a TICK beside the answer please read This $\endgroup$– Advil SellCommented Feb 17, 2019 at 12:37
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You are correct acyl hydrazide can be converted into acyl azide by adding $\ce{HNO2}$ also you wrote that the $\ce{NH2}$ group of hydrazide will be diazotisated making a $\ce{N2+}$ group hence I am assuming that you know the mechanism, after diazotisation the adjacent $\ce{N}$ donate the lone pair to the $\ce{N2+}$ group making the final product as acyl azide.
The mechanism scheme is in the following picture :
