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Jun 4, 2018 at 21:18 comment added Raoul Kessels @Mithoron I have edited the question to change the C4H4O to $\ce{C6H4O}$
Jun 4, 2018 at 18:49 history edited Raoul Kessels CC BY-SA 4.0
added 7 characters in body
Jun 4, 2018 at 14:08 answer added Raoul Kessels timeline score: 4
Jun 2, 2018 at 17:11 comment added Mithoron C6H4O has appropriate mass not C4 BTW there's no problem at all with losing two groups, there are further losses too, and peak 43 is even higher.
Jun 2, 2018 at 16:30 review First posts
Jun 2, 2018 at 16:32
Jun 2, 2018 at 16:27 history asked fardeem CC BY-SA 4.0