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Mar 4, 2018 at 13:52 comment added porphyrin no, much, much simpler, I wanted only to give a familiar example where addition does not work. We can measure the difference in temperature between inside (say 20 C) and outside (say -5 C) which is 25 degrees difference but we do not add the temperatures as this makes no sense (15 degrees). Similarly with potentials.
Mar 4, 2018 at 13:25 comment added Gaurang Tandon Oh, I see where you're going. Can you elaborate on that relation with temperature? Do you mean to say that a solid at 300K when touched with a solid at 400K, through conduction their final temperature will be...?
Mar 4, 2018 at 13:22 comment added porphyrin The value you need is always the difference in potential which is ok just as we can have a difference in temperature but not a sum. The values themselves are ultimately referenced to the hydrogen electrode at $0$V. Your confusion seems to be that you want to add potentials. (The addition bit I mentioned is just a way of remembering how to do the calculation, so I hope I did'n't confuse )
Mar 4, 2018 at 11:45 comment added Gaurang Tandon Actually, my question was exactly why the addition of redox potentials works the way it does, because according to me their addition should be invalid as they are intensive properties.
Mar 4, 2018 at 11:30 history edited porphyrin CC BY-SA 3.0
typo
Mar 4, 2018 at 11:28 comment added porphyrin Its the same if you make $E^\text{o}$ the emf of the cell which is the convention. I used $\Delta E^\text{o} $ only because you measure a difference in $E$ but I will change it, :)
Mar 4, 2018 at 11:25 comment added Gaurang Tandon Actually, I was taught $\Delta G=-nFE^\circ$ and not $\Delta G=-nF\Delta E^\circ$. The latter is your first equation...
Mar 4, 2018 at 11:18 history answered porphyrin CC BY-SA 3.0