In a material that I use to study High School Organic Chemistry, the bromination of ethyl substituted benzaldehydes is given as follows:

$\ce{-CHO}$ is a meta directing group, and $\ce{-C2H5}$ is an ortho, para directing group. So isn't some of the products given wrong?

For example, let's take the bromination of ortho ethyl benzaldehyde. Shouldn't the 2nd product's bromine be in a way that is in position 4 wrt $\ce{-C2H5}$ and position 3 wrt $\ce{-CHO}$?

In the meta ethyl benzaldehyde case, why is the $\ce{-CHO}$ group not affecting the position of $\ce{Br}$? Even though it is meta directing, $\ce{Br}$ doesn't seem to substitute the $\ce{H}$ in the meta position of $\ce{-CHO}$

I searched the internet for more information regarding such reactions, and could not find any helpful results for this case.

In a material that I use to study High School Organic Chemistry, the bromination of ethyl substituted benzaldehydes is given as follows:

Source: FIITJEE Grand Masters Package - Chemistry (JEE Preparatory Material)

$\ce{-CHO}$ is a meta directing group, and $\ce{-C2H5}$ is an ortho, para directing group. So isn't some of the products given wrong?

For example, let's take the bromination of ortho ethyl benzaldehyde. Shouldn't the 2nd product's bromine be in a way that is in position 4 wrt $\ce{-C2H5}$ and position 3 wrt $\ce{-CHO}$?

In the meta ethyl benzaldehyde case, why is the $\ce{-CHO}$ group not affecting the position of $\ce{Br}$? Even though it is meta directing, $\ce{Br}$ doesn't seem to substitute the $\ce{H}$ in the meta position of $\ce{-CHO}$

I searched the internet for more information regarding such reactions, and could not find any helpful results for this case.