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May 8, 2019 at 14:55 comment added Michael Lautman As a general rule, carbocations do not form in the presence of strong bases. This means that $\ce{S_N1}$ or $\ce{E1}$ mechanisms are ruled out immediately. It is important to look at all of the factors that are at play in the reaction: the alkyl halide, the nucleophile/base, the solvent and the temperature. It is the cumulative effect of these that determines the major product, not any one of them alone.
S Feb 13, 2018 at 4:44 history edited Martin - マーチン CC BY-SA 3.0
removed unnecessary MathJax
S Feb 13, 2018 at 4:44 history suggested Gaurang Tandon CC BY-SA 3.0
chem formatting
Feb 13, 2018 at 2:38 review Suggested edits
S Feb 13, 2018 at 4:44
Feb 13, 2018 at 0:44 comment added bonCodigo @J.Se take a look at this, will try to post a bit more detailed explanation.
Feb 12, 2018 at 20:51 comment added J.Se Why is Sn2 major? I'm having difficult time understanding how a polar protic solvent can result in a Sn2 reaction. Isn't elimination reactions favoured in polar protic solvents?
Feb 12, 2018 at 17:46 history answered Soumik Das CC BY-SA 3.0