This is a formally $\ce{Mn(VII)}$a manganese(VII) compound and hence there are no $3d$3d electrons.
The four $\ce{O^2-}$ ions are considered to be donating two electrons each to the $\ce{Mn}$ Atomic Orbitalsatomic orbitals. Now most chemists didn't realize that tetrahedral "hybridization"Tetrahedral "hybridisation" can be achieved by using the $4s,~3dxy,~3dyz$$\mathrm{4s},~\mathrm{3d}_{xy},~\mathrm{3d}_{yz}$, and $3dxz$$\mathrm{3d}_{xz}$ AOs. Since in $\ce{Mn(VII)}$Mn(VII) the $3d$$\mathrm{3d}$ AOs are lower in energy than the 4s$\mathrm{4s}$ and 4p$\mathrm{4p}$ AOs, the "hybridization""hybridisation" is best considered as $d^3s$$\mathrm{d^3s}$.
I have put "hybridization""hybridisation" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly $4s,~3dxy,~3dyz,~ 3dxz$$\mathrm{4s},~\mathrm{3d}_{xy},~\mathrm{3d}_{yz}$ character but they'll also probably mix some 4p$\mathrm{4p}$ character in there for good measure!