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orthocresol
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This is a formally $\ce{Mn(VII)}$a manganese(VII) compound and hence there are no $3d$3d electrons.

The four $\ce{O^2-}$ ions are considered to be donating two electrons each to the $\ce{Mn}$ Atomic Orbitalsatomic orbitals. Now most chemists didn't realize that tetrahedral "hybridization"Tetrahedral "hybridisation" can be achieved by using the $4s,~3dxy,~3dyz$$\mathrm{4s},~\mathrm{3d}_{xy},~\mathrm{3d}_{yz}$, and $3dxz$$\mathrm{3d}_{xz}$ AOs. Since in $\ce{Mn(VII)}$Mn(VII) the $3d$$\mathrm{3d}$ AOs are lower in energy than the 4s$\mathrm{4s}$ and 4p$\mathrm{4p}$ AOs, the "hybridization""hybridisation" is best considered as $d^3s$$\mathrm{d^3s}$. 

I have put "hybridization""hybridisation" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly $4s,~3dxy,~3dyz,~ 3dxz$$\mathrm{4s},~\mathrm{3d}_{xy},~\mathrm{3d}_{yz}$ character but they'll also probably mix some 4p$\mathrm{4p}$ character in there for good measure!

This is a formally $\ce{Mn(VII)}$ compound and hence there are no $3d$ electrons.

The four $\ce{O^2-}$ ions are considered to be donating two electrons each to the $\ce{Mn}$ Atomic Orbitals. Now most chemists didn't realize that tetrahedral "hybridization" can be achieved by using the $4s,~3dxy,~3dyz$, and $3dxz$ AOs. Since in $\ce{Mn(VII)}$ the $3d$ AOs are lower in energy than the 4s and 4p AOs the "hybridization" is best considered as $d^3s$. I have put "hybridization" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly $4s,~3dxy,~3dyz,~ 3dxz$ character but they'll also probably mix some 4p character in there for good measure!

This is formally a manganese(VII) compound and hence there are no 3d electrons.

The four $\ce{O^2-}$ ions are considered to be donating two electrons each to the atomic orbitals. Tetrahedral "hybridisation" can be achieved by using the $\mathrm{4s},~\mathrm{3d}_{xy},~\mathrm{3d}_{yz}$, and $\mathrm{3d}_{xz}$ AOs. Since in Mn(VII) the $\mathrm{3d}$ AOs are lower in energy than the $\mathrm{4s}$ and $\mathrm{4p}$ AOs, the "hybridisation" is best considered as $\mathrm{d^3s}$. 

I have put "hybridisation" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly $\mathrm{4s},~\mathrm{3d}_{xy},~\mathrm{3d}_{yz}$ character but they'll also probably mix some $\mathrm{4p}$ character in there for good measure!

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M.A.R.
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This is a formally Mn(VII) compoud$\ce{Mn(VII)}$ compound and hence there are no 3d$3d$ electrons. 

The four $\ce{O^2-}$ ions are considered to be donating two electrons each to the $\ce{Mn}$ Atomic Orbitals. Now most chemists didn't realize that tetrahedral "hybridization" can be achieved by using the 4s,3dxy,3dyz$4s,~3dxy,~3dyz$, and 3dxz$3dxz$ AOs. Since in Mn(VII)$\ce{Mn(VII)}$ the 3d$3d$ AOs are lower in energy than the 4s and 4p AOs the "hybridization" is best considered as d^3s$d^3s$. I have put "hybridization" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly 4s,3dxy,3dyz, 3dxz$4s,~3dxy,~3dyz,~ 3dxz$ character but they'll also probably mix some 4p character in there for good measure!

This is a formally Mn(VII) compoud and hence there are no 3d electrons. The four $\ce{O^2-}$ ions are considered to be donating two electrons each to the $\ce{Mn}$ Atomic Orbitals. Now most chemists didn't realize that tetrahedral "hybridization" can be achieved by using the 4s,3dxy,3dyz, and 3dxz AOs. Since in Mn(VII) the 3d AOs are lower in energy than the 4s and 4p AOs the "hybridization" is best considered as d^3s. I have put "hybridization" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly 4s,3dxy,3dyz, 3dxz character but they'll also probably mix some 4p character in there for good measure!

This is a formally $\ce{Mn(VII)}$ compound and hence there are no $3d$ electrons. 

The four $\ce{O^2-}$ ions are considered to be donating two electrons each to the $\ce{Mn}$ Atomic Orbitals. Now most chemists didn't realize that tetrahedral "hybridization" can be achieved by using the $4s,~3dxy,~3dyz$, and $3dxz$ AOs. Since in $\ce{Mn(VII)}$ the $3d$ AOs are lower in energy than the 4s and 4p AOs the "hybridization" is best considered as $d^3s$. I have put "hybridization" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly $4s,~3dxy,~3dyz,~ 3dxz$ character but they'll also probably mix some 4p character in there for good measure!

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stochastic13
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This is a formally Mn(VII) cmpdcompoud and hence there are no 3d e⁻selectrons. The four O^2-$\ce{O^2-}$ ions are considered to donatebe donating two e⁻electrons each to the Mn AOs$\ce{Mn}$ Atomic Orbitals. Now most chemists don't realizeddidn't realize that tetrahedral "hybridization" can be achieved by using the 4s,3dxy,3dyz, and 3dxz AOs. Since in Mn(VII) the 3d AOs are lower in energy than the 4s and 4p AOs the "hybridization" is best considered as d^3s. I have put "hybridization" in quotes because it is not used in advanced chemchemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly 4s,3dxy,3dyz, 3dxz character but they'll also probably mix some 4p character in there for good measure!

This is a formally Mn(VII) cmpd and hence there are no 3d e⁻s. The four O^2- ions are considered to donate two e⁻ each to the Mn AOs. Now most chemists don't realized that tetrahedral "hybridization" can be achieved by using the 4s,3dxy,3dyz, and 3dxz AOs. Since in Mn(VII) the 3d AOs are lower in energy than the 4s and 4p AOs the "hybridization" is best considered as d^3s. I have put "hybridization" in quotes because it is not used in advanced chem (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly 4s,3dxy,3dyz, 3dxz character but they'll also probably mix some 4p character in there for good measure!

This is a formally Mn(VII) compoud and hence there are no 3d electrons. The four $\ce{O^2-}$ ions are considered to be donating two electrons each to the $\ce{Mn}$ Atomic Orbitals. Now most chemists didn't realize that tetrahedral "hybridization" can be achieved by using the 4s,3dxy,3dyz, and 3dxz AOs. Since in Mn(VII) the 3d AOs are lower in energy than the 4s and 4p AOs the "hybridization" is best considered as d^3s. I have put "hybridization" in quotes because it is not used in advanced chemistry (it is an artifact!) but it is correct in saying that the bonding MOs contain mostly 4s,3dxy,3dyz, 3dxz character but they'll also probably mix some 4p character in there for good measure!

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