2 added 35 characters in body edited May 23 '17 at 11:15 Nilay Ghosh 10.6k1212 gold badges4747 silver badges116116 bronze badges Since I2IX2$$\ce{I2}$$ is a non-polar covalent molecule, it does not ionize in water. It cannot also be soluble in the polar water. KIKI,$$\ce{KI}$$ which is a polar, ionic compound, will ionize and dissolve in water. When KI$$\ce{KI}$$ dissolves in water, it ionizes to K+KX+$$\ce{K+}$$ and I−IX−$$\ce{I-}$$. The I−IX−$$\ce{I−}$$ will react with I2IX2$$\ce{I2}$$ to form the complex ion I3−IX3X−$$\ce{I3-}$$. I3−IX3X−$$\ce{I3-}$$ being negatively charged will dissolve in water. Since I2IX2 is a non-polar covalent molecule, it does not ionize in water. It cannot also be soluble in the polar water. KIKI, which is a polar, ionic compound, will ionize and dissolve in water. When KI dissolves in water, it ionizes to K+KX+ and I−IX−. The I−IX− will react with I2IX2 to form the complex ion I3−IX3X−. I3−IX3X− being negatively charged will dissolve in water. Since $$\ce{I2}$$ is a non-polar covalent molecule, it does not ionize in water. It cannot also be soluble in the polar water. $$\ce{KI}$$ which is a polar, ionic compound, will ionize and dissolve in water. When $$\ce{KI}$$ dissolves in water, it ionizes to $$\ce{K+}$$ and $$\ce{I-}$$. The $$\ce{I−}$$ will react with $$\ce{I2}$$ to form the complex ion $$\ce{I3-}$$. $$\ce{I3-}$$ being negatively charged will dissolve in water. 1 answered May 23 '17 at 10:52 Since I2IX2 is a non-polar covalent molecule, it does not ionize in water. It cannot also be soluble in the polar water. KIKI, which is a polar, ionic compound, will ionize and dissolve in water. When KI dissolves in water, it ionizes to K+KX+ and I−IX−. The I−IX− will react with I2IX2 to form the complex ion I3−IX3X−. I3−IX3X− being negatively charged will dissolve in water.