# Return to Answer

 2 Added MathJax formatting. edited Apr 6 '17 at 18:22 airhuff 15k77 gold badges3232 silver badges158158 bronze badges Given that a 2-place balance is no more accurate than +/- 0.01 g$$\pu{+/- 0.01 g}$$, you shouldcan say that the two measurements were within 0.01 g$$\pu{0.01 g}$$ of the average, 12.53$$\pu{12.53g}$$, andthen just use that (thethis average) for your calculations. Given that a 2-place balance is no more accurate than +/- 0.01 g, you should say that the two measurements were within 0.01 g of the average, 12.53, and just use that (the average). Given that a 2-place balance is no more accurate than $$\pu{+/- 0.01 g}$$, you can say that the two measurements were within $$\pu{0.01 g}$$ of the average, $$\pu{12.53g}$$, then just use this average for your calculations. 1 answered Mar 7 '17 at 4:35 airhuff 15k77 gold badges3232 silver badges158158 bronze badges Given that a 2-place balance is no more accurate than +/- 0.01 g, you should say that the two measurements were within 0.01 g of the average, 12.53, and just use that (the average).