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I know this might be a silly question but I am confused with different answers of internet. My question is:

Molar conductivity is given as:

Molar conductivity = $k÷M$$\frac{\kappa}{M}$.

SIS.I. unit of : k$\kappa$ is S/m &$\pu{Sm}^{-1}$ &

M$M$ is in mol/$m^3$$\mathrm{mol \, m^{-3}}$.

Thus, Molar conductivity in SI is S$m^2$/$mol$ ....S.I.(1) is $\mathrm{S \, m^2 \, mol^{-1}} \tag{1}$

When I substitute 1m=100cm1 m = 100 cm in (1). I got new unit as [S$cm^2$/$mol$$10^4$$[\mathrm{S \, cm^2 \, mol^{-1}}] \times10^4$. But in a book It was given as [S$cm^2$/$mol$$10^3$ ........(2), where

$[\mathrm{S \, cm^2 \, mol^{-1}}] \times 10^3 \tag{2}$

where they have taken S in S/cm and molarity in mol/Litrelitre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit given in (2).

I know this might be a silly question but I am confused with different answers of internet. My question is:

Molar conductivity is given as:

Molar conductivity = $k÷M$.

SI unit of : k is S/m &

M is in mol/$m^3$.

Thus Molar conductivity in SI is S$m^2$/$mol$ ......(1)

When I substitute 1m=100cm in (1). I got new unit as [S$cm^2$/$mol$$10^4$. But in a book It was given as [S$cm^2$/$mol$$10^3$ ........(2), where they have taken S in S/cm and molarity in mol/Litre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit given in (2).

I know this might be a silly question but I am confused with different answers of internet. My question is:

Molar conductivity is given as:

Molar conductivity = $\frac{\kappa}{M}$.

S.I. unit of : $\kappa$ is $\pu{Sm}^{-1}$ &

$M$ is in $\mathrm{mol \, m^{-3}}$.

Thus, Molar conductivity in S.I. is $\mathrm{S \, m^2 \, mol^{-1}} \tag{1}$

When I substitute 1 m = 100 cm in (1). I got new unit as $[\mathrm{S \, cm^2 \, mol^{-1}}] \times10^4$. But in a book It was given as

$[\mathrm{S \, cm^2 \, mol^{-1}}] \times 10^3 \tag{2}$

where they have taken S in S/cm and molarity in mol/litre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit given in (2).

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I know this might be a silly question but I am confused with different answers of internet. My question is:

Molar conductivity is given as:

Molar conductivity = $k÷M$.

SI unit of : k is S/m &

M is in mol/$m^3$.

Thus Molar conductivity in SI is S$m^2$/$mol$ ......(1)

When I substitute 1m=100cm in (1). I got [Snew unit as [S$cm^2$/$mol$$10^4$. But in a book It was given as [S$cm^2$/$mol$$10^3$ ........(2), When S iswhere they have taken S in S/cm and molarity in mol/Litre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit given in (2).

I know this might be a silly question but I am confused with different answers of internet. My question is:

Molar conductivity is given as:

Molar conductivity = $k÷M$.

SI unit of : k is S/m &

M is in mol/$m^3$.

Thus Molar conductivity in SI is S$m^2$/$mol$ ......(1)

When I substitute 1m=100cm I got [S$cm^2$/$mol$$10^4$ But in a book It was given as [S$cm^2$/$mol$$10^3$ ........(2) When S is taken in S/cm and molarity in mol/Litre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit (2).

I know this might be a silly question but I am confused with different answers of internet. My question is:

Molar conductivity is given as:

Molar conductivity = $k÷M$.

SI unit of : k is S/m &

M is in mol/$m^3$.

Thus Molar conductivity in SI is S$m^2$/$mol$ ......(1)

When I substitute 1m=100cm in (1). I got new unit as [S$cm^2$/$mol$$10^4$. But in a book It was given as [S$cm^2$/$mol$$10^3$ ........(2), where they have taken S in S/cm and molarity in mol/Litre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit given in (2).

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Avi
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I know this might be a silly question but I am confused with different answers of internet. My question is:

For Molar conductivity is given as:

Molar conductivity = $k÷M$.

SI unit of : k is S/m & &

M is in mol/$m^3$.

Thus Molar conductivity is in SI is S$m^2$$(mol)^-1$$m^2$/$mol$ ......(1)

When I substitute 1m=100cm I got S$cm^2$$mol^-1$×[S$cm^2$/$mol$$10^4$ But in a book It was given as S$cm^2$$mol^-1$×[S$cm^2$/$mol$$10^3$.   ........(2) When S is taken in S/cm and molarity in mol/Litre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit (2).

I know this might be a silly question but I am confused with different answers of internet. My question is:

For Molar conductivity = $k÷M$.

SI unit of : k is S/m &

M is in mol/$m^3$.

Thus Molar conductivity is in S$m^2$$(mol)^-1$......(1)

When I substitute 1m=100cm I got S$cm^2$$mol^-1$×$10^4$ But in a book It was given as S$cm^2$$mol^-1$×$10^3$. ........(2) When S is taken in S/cm and molarity in mol/Litre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit (2).

I know this might be a silly question but I am confused with different answers of internet. My question is:

Molar conductivity is given as:

Molar conductivity = $k÷M$.

SI unit of : k is S/m &

M is in mol/$m^3$.

Thus Molar conductivity in SI is S$m^2$/$mol$ ......(1)

When I substitute 1m=100cm I got [S$cm^2$/$mol$$10^4$ But in a book It was given as [S$cm^2$/$mol$$10^3$  ........(2) When S is taken in S/cm and molarity in mol/Litre. But where I was wrong.

If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit (2).

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Source Link
Avi
  • 611
  • 3
  • 12
  • 21
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Source Link
Avi
  • 611
  • 3
  • 12
  • 21
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