I know this might be a silly question but I am confused with different answers of internet. My question is:
Molar conductivity is given as:
Molar conductivity = $k÷M$$\frac{\kappa}{M}$.
SIS.I. unit of : k$\kappa$ is S/m &$\pu{Sm}^{-1}$ &
M$M$ is in mol/$m^3$$\mathrm{mol \, m^{-3}}$.
Thus, Molar conductivity in SI is S$m^2$/$mol$ ....S.I.(1) is $\mathrm{S \, m^2 \, mol^{-1}} \tag{1}$
When I substitute 1m=100cm1 m = 100 cm in (1). I got new unit as [S$cm^2$/$mol$]×$10^4$$[\mathrm{S \, cm^2 \, mol^{-1}}] \times10^4$. But in a book It was given as [S$cm^2$/$mol$]×$10^3$ ........(2), where
$[\mathrm{S \, cm^2 \, mol^{-1}}] \times 10^3 \tag{2}$
where they have taken S in S/cm and molarity in mol/Litrelitre. But where I was wrong.
If you feel the question too confusing just explain me How I can convert that SI unit given in (1) into unit given in (2).