In the second paragraph of the image you can see that p-aminobenzenesulfonic acid is more stable.

But according to me, o-aminobenzenesulfonic acid should be more stable as there is six-member cycle of H-bonding.

Am I wrong in my claim?

According to a textbook by K. L. Chugh:

Sulfonation [of aniline] is a reversible reaction. The p-isomer, being more stable, does not get desulfonated easily. Hence, p-sulfanilic acid is the major product.

I am curious as to why the ortho isomer (2-aminobenzenesulfonic acid) is not more thermodynamically stable. There is a possibility of intramolecular hydrogen bonding (in a six-membered ring):

Why is the para isomer (4-aminobenzenesulfonic acid) favoured?

In the second paragraph of the image you can see that p-aminobenzenesulfonic acid is more stable.

But according to me, o-aminobenzenesulfonic acid should be more stable as there is six-member cycle of H-bonding.

Am I wrong in my claim?

In the second paragraph of the image you can see that p-aminobenzenesulfonic acid is more stable.

But according to me, o-aminobenzenesulfonic acid should be more stable as there is six-member cycle of H-bonding.

Am I wrong in my claim?